Example2:
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| Example 2 |
172.16.0.0/16
Answer:
v We
need Extra 2 Host’s to Connect Two Routers
i.e. R1 to R2 – Two IP
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| Host Order Selection |
v
So Totally we need 5 Subnets
v
Important to write Hosts in Descending Order
v
If we Choose CIDR, we Lost lot of IP’s
Ex: in Vlan
A, 100 Host needed. So Remaining 155 Waste. So we Choose VLSM
Vlan C: 1000 Host
v
So 10 bit's is enough to get 1000 host's
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| 0th Subnet |
- We Never Use 0th Subnet
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| Vlan-C Subnet |
Network
ID: 172.16.4.0
1st
Host ID: 172.16.4.1
Last
Host ID: 172.16.7.254
Broadcast
ID: 172.16.7.255
Subnet
Mask: 255.255.252.0
Vlan B: 500 Host
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| Calculating Host's |
- So 9 bit's is enough to get 500 host's
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| Vlan B Subnet |
- We Put '1' in 4th bit Because Current Network ID is next IP of Last Vlan Broadcast ID
Network ID: 172.16.8.0
1st Host ID: 172.16.8.1
Last Host ID: 172.16.9.254
Broadcast ID: 172.16.9.255
Subnet Mask: 255.255.254.0
Vlan A: 100 Host
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| Calculating Host's |
v
So 7 bit's is enough
to get 100 host's
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| Vlan-A Subnet |
v
Current Network ID is
next IP of Last Vlan Broadcast ID
Network ID: 172.16.10.0
1st Host ID: 172.16.10.1
Last Host ID: 172.16.10.126
Broadcast ID: 172.16.10.127
Subnet Mask: 255.255.255.128
Vlan D: 50 Host
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| Calculating Host's |
v
So 6 bit's is enough
to get 50 host's
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| Vlan - D Subnet |
v
Current Network ID is
next IP of Last Vlan Broadcast ID
Network ID: 172.16.10.128
1st Host ID: 172.16.10.129
Last Host ID: 172.16.10.190
Broadcast ID: 172.16.10.191
Subnet Mask: 255.255.255.192
R1 to R2 : 2 Host
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| Calculating Host's |
v So 2 bit's is enough to get 4 Host's
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| R1 to R2 Subnet |
v
Current Network ID is
next IP of Last Vlan Broadcast ID
Network ID: 172.16.10.192
1st Host ID: 172.16.10.193
Last Host ID: 172.16.10.194
Broadcast ID: 172.16.10.195
Subnet Mask: 255.255.255.252













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