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Thursday, June 21, 2018
Example 7: Classless Inter-Domain Routing (CIDR) (Super-netting)
Question:
IP : 10.255.50.7/17
Find the
Network ID?
Answer:
/17 Means
17 Bits are Network Bits
Without
Writing Mask, we are mentioning like this
![]() |
| Converting IP Address to Binary |
50 – 00110010
![]() |
| IP and Subnet Mask in Binary |
Network ID
Rule -> Network – Constant
Host - Zero’s
![]() |
| Make Host as 0's |
Network ID is 10.255.0.0
Example 6: Classless Inter-Domain Routing (CIDR) (Super-netting)
Question:
IP : 172.16.1.126
Subnet Mask
: 255.255.255.128
Find the
Network ID?
Answer:
![]() |
| Converting IP Address to Binary |

| Converting IP Address to Binary |
126 – 11111110 128
– 01000000
![]() |
| IP and Subnet Mask in Binary |
Network ID
Rule -> Network – Constant
Host - Zero’s
![]() |
| Make Host as 0's |
So Network ID is 172.16.1.0
Example 5: Classless Inter-Domain Routing (CIDR) (Super-netting)
Question:
IP : 172.16.5.225
Subnet Mask
: 255.255.255.192
Find the
Network ID?
Answer:
![]() |
| Converting IP Address to Binary |

Converting IP Address to Binary
For IP 192, Binary is 11000000
For IP 225, Binaryl is 11100001
![]() |
| IP and Subnet Mask in Binary |
24 + 2 (2 Bits Borrowed) = 26 Bits Network Portion
Network ID Rule -> Network – Constant
Host - Zero’s
![]() |
| Make Host as 0's |
So Network ID is 172.16.5.192
Example 4: Classless Inter-Domain Routing (CIDR) (Super-netting)
Question:
IP - 192.168.1.0 / 24
Need 3
Subnet with Each 50
Hosts?
Answer:
![]() |
| Result Imagination Diagram |
Already Class C Given.So we will Calculate host using class C
![]() |
| Calculating Host's |
So 6 bit's
is enough to get 50 hosts
![]() |
| Sub-netting |
1st Subnet: (Vlan 1)
![]() |
| 1st Subnet |
Network ID :
192.168.1.64
1st Host ID : 192,168.1.65
Last Host ID : 192.168.1.126
Broadcast ID : 192.168.1.127
Subnet Mask : 255.255.255.192
2nd Subnet (Vlan 2)
![]() |
| 2nd Subnet |
Network ID :
192.168.1.128
1st Host ID : 192.168.1.129
Last Host ID :
192.168.1.190
Broadcast ID :
192.168.1.191
Subnet Mask : 255.255.255.192
3rd Subnet (Vlan 3)
![]() |
3rd Subnet
|
Network ID :
192.168.1.192
1st Host ID : 192.168.1.193
Last Host ID :
192.168.1.254
Broadcast ID :
192.168.1.255
Subnet Mask : 255.255.255.192
Example 3: Classless Inter-Domain Routing (CIDR) (Super-netting)
Question:
![]() |
| Example 3 |
Answer:
v We Need
3000 Host
v Class – B
is enough to get 3000 Host (We can Choose Class-A Also)
![]() |
| Calculating Host's |
So 10 Bit is Enough to get 1000 Host
![]() |
| Sub-netting |
1st Subnet: (Vlan X)
Network ID : 172.16.4.0
1st
Host ID : 172.16.4.1
Last Host
ID : 172.16.7.254
Broadcast
ID : 172.16.7.255
Subnet Mask : 255.255.252.0
2nd Subnet: (Vlan Y)
Network ID :
172.16.8.0
1st Host ID : 172.16.8.1
Last Host ID : 172.16.11.254
Broadcast ID : 172.16.11.255
Subnet Mask : 255.255.252.0
3rd Subnet: (Vlan Z)
Network ID :
172.16.12.0
1st Host ID : 172.16.12.1
Last Host ID : 172.16.15.254
Broadcast ID : 172.16.15.255
Subnet Mask : 255.255.252.0
Example 1: Classless Inter-Domain Routing (CIDR) (Super-netting)
Question:
![]() |
| Example 1 |
v In NITT
Campus,
For Admin
we need 100 Host (Vlan name – Vlan A)
For
Security – 100 Host (Vlan B)
Dean – 100
Host (Vlan C)
So totally
we need 300 Host
Answer:
v If we
choose Class C, Last bit only Host. So we can choose maximum 255 Host only, but
we need 300 Host. So we choose Class-B or Class-A
v Now We Choose Class-B to Solve
v Now We Choose Class-B to Solve
![]() |
| Sub-netting |
v We Never
Use 0th Subnet
1st Subnet: (Vlan A)
![]() |
| 1st Subnet |
N/w ID:
172.16.0.128
1st
Host ID: 172.16.0.129
Last Host ID:
172.16.0.254
Broadcast ID:
172.16.0.255
Subnet Mask:
255.255.255.128
2nd Subnet: (Vlan B)
![]() |
| 2nd Subnet |
N/w ID:
172.16.1.0
(Previous Vlan next broadcast IP is this Vlan
network id)
1st
Host ID: 172.16.1.1
Last Host ID:
172.16.1.126
Broadcast ID:
172.16.1.127
Subnet Mask:
255.255.255.128
3rd Subnet: (Vlan C)
![]() |
| 3rd Subnet |
N/w ID:
172.16.1.128
1st
Host ID: 172.16.1.129
Last Host ID:
172.16.1.254
Broadcast ID:
172.16.1.255
Subnet Mask:
255.255.255.128
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